1.

A + 2B+ 3C AB_2 C_3 Reaction of 6.0 g of A, 6.0 xx 10^(23)atoms of B, and 0.036 mol of C yields 4.8 g of compoundAB_(2)C_(3). If the atomic mass of A and C are 60 and 80 amu, respectively. The atomic mass of B is:(Avogadro number= 6 xx 10^(23))

Answer»

70 amu
60 amu
50 amu
40 amu

Solution :`{:(,A,+,2B,+,3C,rarr,AB_(2)C_(3)),(t = 0,0.1,,1,,0.036,,0):}`
C is limiting regent therefore MOLES of `AB_(2)C_(3)`will be 0.012.
Mass of 0.012 mol `AB_(2)C_(3)`is 4.8 gm
Mass of 1 mol `AB_(2)C_(3)`is `(4.8)/(0.012) = 400`
Molar mass of`AB_(2)C_(3)`is 400 gm
`A + 2B + 3C = 400 gm`
`60 + 2B + 240 = 400 rArr B = 50`
ATOMIC mass of B is 50u


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