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A `2kg` block slides on a horizontal floor with the a speed of `4m//s` it strikes a uncompressed spring , and compresses it till the block is motionless . The kinetic friction force is compresses is `15 N` and spring constant is `10000 N//m` . The spring byA. 5.5 cmB. 2.5 cmC. 11.0 cmD. 8.5 cm |
Answer» Correct Answer - C `(1)/(2)mv^2=(1)/(2)kx^2+W_f` `(1)/(2)(2)(4)^2=(1)/(2)(10000)x^2+f_(k)x` `16=5xx10^3x^3+15x` `5xx10^3x^3+15x-16=0` `x=(-15+-sqrt((15)^2+4xx5xx10^2xx16))/(5xx10^3)` `=(11)/(100)m=11cm` |
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