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A `2kg` block slides on a horizontal floor with the a speed of `4m//s` it strikes a uncompressed spring , and compresses it till the block is motionless . The kinetic friction force is compresses is `15 N` and spring constant is `10000 N//m` . The spring by |
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Answer» `KE = (1)/(2) mv^(2) = W_("friction") + (1)/(2) Kx^(2)` `rArr (1)/(2) xx 2xx 4^(2) = 15 x + (1)/(2) xx 10000 xx x^(2)` `rArr 5000 x^(2) + 15 x - 16 = 0` `rArr x = 0.055 m` or `x = 5.5 cm`. |
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