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A `2kg` block slides on a horizontal floor with the a speed of `4m//s` it strikes a uncompressed spring , and compresses it till the block is motionless . The kinetic friction force is compresses is `15 N` and spring constant is `10000 N//m` . The spring byA. `2.5`B. `11.0`C. `8.5`D. `5.5` |
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Answer» Correct Answer - D Let the spring be compressed by `x`. Loss in `KE` of block = Gain in `PE` of spring + Work done against friction `rArr (1)/(2) xx 2 xx4^(2) =(1)/(2) 1000 x^(2) + 15 x` On solving, we get `x = 5.5 cm`. |
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