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A `2MeV` proton is moving perpendicular to a uniform magnetic field `2.5` tesla. The force on the proton isA. `8xx10^-10N`B. `4xx10^-10N`C. `6xx10^-10N`D. `8xx10^-12N` |
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Answer» Correct Answer - D `E_k=(1)/(2)mv^2{v=2xx10^7 m//s)`. `F=qv Bsin 90 =8xx10^-12N`. |
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