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InterviewSolution
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A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire ? |
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Answer» Solution :We know that the magnetic field INSIDE a solenoid is uniform and directed along its axis. Hence, angle `theta` between the magnetic field and the current carrying wire, placed PERPENDICULAR to the solenoid axis, is `90^@`. Moreover `I = 10 A, l = 3 CM = 3 xx 10^(-2) m and B = 0.27 T` `:. F = B I l SIN theta = 0.27 xx 10 xx 3 xx 10^(-2) xx sin 90^@ = 8,1 xx 10^(-2) N`. |
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