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A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T.What is the magnetic force on the wire ? |
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Answer» SOLUTION :I=3.0cm `= 3.0 xx 10^(2-) m, I=10A, B =0.27 T` `F=Bil = 0.27 xx 10xx 3 xx 10^(-2) = 8.1 xx 10^(-2) N` |
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