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A 300W carrier is modulated to a depth 75%. The total powerin the modulated wave is |
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Answer» Solution :`P_(C)=300W, MU=75%=0.75` `P_(t)=P_(c)(1+(mu^(2))/(2)) ` o r `P_(t)= 300(1+((0.75)^(2))/(2))= 384W ` |
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