1.

A 300W carrier is modulated to a depth 75%. The total powerin the modulated wave is

Answer»

<P>200W
284W
320W
384W

Solution :`P_(C)=300W, MU=75%=0.75`
`P_(t)=P_(c)(1+(mu^(2))/(2)) ` o r `P_(t)= 300(1+((0.75)^(2))/(2))= 384W `


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