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(a) 31 g of an unknown molecular material is dissolved in 500 g of water. The resulting solution freezes at 27.14 K. Calculate the molar mass of the material. [Given: K, for water 1.86 Kgmol^(-1), T_(f)^(0) of water=273К].(b) What is reverse osmosis? Mention its use. |
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Answer» Solution :(a)`M_(B) = K_(f)W_(B)1000/DeltaT_(f)W_(A)` `Delta(T)_(f) =``T^(0)_(f) - T_(f)=273-271.14K=1.86K` `M_(B)= 1.86xx31xx1000/(1.86xx500)=62gmol^(-1)` |
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