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A `3kg` mass and `4kg` mass are placed on `X` and `Y` axes at a distance of `1` meter from the origin and a `1kg` mass is placed at the origin. Then the resultant gravitational force on `1kg` mass isA. `7G`B. `G`C. `5G`D. `3G` |
Answer» Correct Answer - C `theta=90^(@), F_(1)=(3G)/(1^(2)), F_(2)=(4G)/(1^(2))` `F=sqrt(F_(1)^(2)+F_(2)^(2)+2F_(1)F_(2)cos theta)` |
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