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A 4.0 kg block is suspended from the ceiling of an elevator through a string having a linear mass desity of `19.2xx10^-3 kgm^-1`. Find the speed (with respect to the string) with which a wave pulse can proceed on the string if the elavator accelerates up at the rate of `2.0ms^-2. Take g=10 ms^-2`. |
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Answer» `mu=19.2xx10^(-3)kg//m` from the free body diagram `T-4g-4a=0` `T=4(a+g)=4(2+10)=48N` wave speed: `v=sqrt((T)/(mu))=sqrt((48)/(19.2xx10^(-3)))=50 m//s` `so n=4` |
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