InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A 4 m long rod of negligible weight is to be balanced about a point 125 cm from one end. A load of 18 kgf is suspended at a point 60 cm from the support on the shorter arm.(a) a weight W is placed 250 cm from the support on the longer arm Find W.(b) If W = 5 kgf, where must it be kept to balance the rod?(c) To which class of lever does it belong? |
|
Answer» Total length of rod=4 m = 400 cm (a) 18kgf load is placed at 60 cm from the support. W kgf weight is placed at 250 cm from the support. By the principle of moments 18 x 60 = W x 250 W = 4.32 kgf (b) Given W=5 kgf 18kgf load is placed at 60 cm from the support. Let 5 kgf of weight is placed at d cm from the support. By the principle of moments 18 x 60 = 5 x d d = 216 cm from the support on the longer arm (c) It belongs to class I lever. |
|