1.

A 400 mg iron capsule contains 100 mg of ferrousfumarate, (CHCOO)_2 Fe. The percentage of iron present in it is approximately

Answer»

`33%`
`25%`
`14%`
`8%`

Solution :Molecular wt. of `(CHCOO)_2Fe`=170
FE present in 100 mg of `(CHCOO)_2Fe=56/170xx100` mg
=32.9 mg
This is present in 400 mg of the CAPSULE .
`therefore` % of Fe in the capsule = `32.9/400xx100`=8.2


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