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A `40Omega` electric heater is connected to a `200V, 50Hz` main supply. The peak value of electric current flowing in the circuit is approx.A. `2.5A`B. `5A`C. `7A`D. `10A`

Answer» Correct Answer - C
`i_(r.m.s)=(V_(r.m.s))/(R)=(200)/(40)=5A implies i_(0) =i_(r.m.s)sqrt(2)=7.07A`


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