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A 44 mH inductor is connected to 220 V, 50 Hz a.c. supply. Determine the rms value of the current in the circuit.

Answer»

Solution :Here, L = 44 mH `=44 xx 10^(-3) H, V_(rms) = 220V` and frequency V= 50 HZ
`therefore I_(rms) = V_(rms)/(L OMEGA) = (V_(rms))/(L.2pi v) = (220)/(44 xx 10^(-3) xx 2 xx 3.14 xx 50) = 15.9` A


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