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A 44 mH inductor is connected to 220 V, 50 Hz a.c. supply. Determine rms value of current in the circuit. |
Answer» Inductance of inductor, `L=44mH=44xx10^(-3)H` Supply voltage, V=220V Frequency, v=50V Angular frequenc, `omega=2piv` Inductive reactivance, `x_(L)= 2pivL=2pixx50xx44xx10^(-3)Omega` Rms value of current is given as: `=(220)/(2pixx50xx44xx10^(-3))=15.92A` Hence, the rms value of current in the circuit is 15.92A. |
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