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A 44 mH inductor is connected to 220 V, 50 Hz ac supply. Determine the rms value of current in the circuit. |
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Answer» Solution :Here `L = 44mH = 44 xx 10^(-3)H`. `v = 50 Hz` `E_(RMS) = 220 V` Reactance of inductor. `X_(L) = L OMEGA = L xx 2pi v` `= 44 xx 10^(-3) xx 2 xx 3.14 xx 50` `= 13.82 Omega` Current (rms) through the CIRCUIT `I_(rms) = (E_(rms))/(X_(L)) = (220)/(13.82) = 15.9A` |
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