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A 44 mH inductor is connected to 220 V, 50 Hz ac supply. The rms value of the current in the circuit is

Answer» As As `I_(rms) = V_(rms)/X_(L)`
Where, `X_(L) = omegaL=2pifL` is the reactance of the inductor
Here, f=50 Hz, L= 44mH = `44 xx 10^(-3)= 13.82Omega`
`therefore` rms value of current in the circuit `I_(rms) = 220/13.82 = 15.9A`


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