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A 44 mH inductor is connected to 220V, 50 Hz ac supply. Determine the rms value of the current in the circuit. |
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Answer» Solution :`X_(L) = OMEGA L ` `= 2pi f L ` `= ( 2) ( 3.14) ( 50) ( 44 XX 10^(-3))` `= 13.816 Omega` `I_(RMS) = ( V_(rms))/( |Z|)` `= ( V_(rms))/( X_(L))( :. ` Here , `|Z | = X_(L))` `= ( 220)/( 13.816)` `= 15.92 A` |
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