1.

A 44 mH inductor is connected to 220V, 50 Hz ac supply. Determine the rms value of the current in the circuit.

Answer»

Solution :`X_(L) = OMEGA L `
`= 2pi f L `
`= ( 2) ( 3.14) ( 50) ( 44 XX 10^(-3))`
`= 13.816 Omega`
`I_(RMS) = ( V_(rms))/( |Z|)`
`= ( V_(rms))/( X_(L))( :. ` Here , `|Z | = X_(L))`
`= ( 220)/( 13.816)`
`= 15.92 A`


Discussion

No Comment Found

Related InterviewSolutions