1.

A 44mH inductor is connected to 220V, 50 Hz ac supply . Determine the rms value of the current in the circuit .

Answer»

Solution :`I_(rms) = (V_(rms) )/(X_L) = (V_(rms) )/(OMEGAL) = (V_(rms) )/(2pi v L) = (220)/(2pi xx 50 xx 4 xx 10^(-3) ) = 15.9 A`


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