1.

A 44mP inductor is connected to 220 V. 50 Hz ac supply. Determine the rms value of the current in the circuit.

Answer»

Solution :Here `L=44m H=44xx10^(-3)H`,
`v=50Hz, E_("RMS")=220V`
`"REACTANCE of inductor, "X_(L)=Lomega=Lxx2piv`
`=44xx10^(-3)xx2xx3.14xx50=13.82Omega`
`"Current (rms) through the circuit"`
`I_("rms")=(E_("rms"))/(X_(L))=(220)/(13.82)=15.9A`


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