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A 44mP inductor is connected to 220 V. 50 Hz ac supply. Determine the rms value of the current in the circuit. |
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Answer» Solution :Here `L=44m H=44xx10^(-3)H`, `v=50Hz, E_("RMS")=220V` `"REACTANCE of inductor, "X_(L)=Lomega=Lxx2piv` `=44xx10^(-3)xx2xx3.14xx50=13.82Omega` `"Current (rms) through the circuit"` `I_("rms")=(E_("rms"))/(X_(L))=(220)/(13.82)=15.9A` |
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