InterviewSolution
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InterviewSolution
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A 4muF capacitor is charged by a 200V supply. It is then disconnected from the supply and is connected to another uncharged 2muF capacitor. How much electrostatic energy of the first capacitor is lost in the form of heat and electrostatic radiation? |
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Answer» Solution :`C_(1)=4 xx 10^(-6)F"V=200V"C_(2)=2 xx 10^(-6)F` `E_(1)=1/2 C_(1)V^(2)=1/2 xx 4 xx 10^(-6)xx 200 x 200=8 xx 10^(-2)J` `Q=C_(1)V=4 xx 10^(-6) xx 200 =8 xx 10^(-4)C` `E_(2)=1/2 (Q_(2))/(C_(1)+C_(2))=1/2 xx (8 xx 10^(-4) xx 8 xx 10^(-2))/(6 xx 10^(-6))=(16)/(3) xx 10^(-2)` `triangleE=8 xx 10^(-2) -(16)/(3) xx 10^(-2) =8/3 x 10^(-2)J` |
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