1.

A 5.2 molal aqueous solution of methyl alcohol, CH_(3)OH, is supplied. What is mole fraction of methyl alcohol in the solution?

Answer»

0.19
0.086
0.05
0.1

Solution :5.2 molalsolution MEANS 5.2 MOLES of the solute `(CH_(3)OH)` are present in 1000 g of water, i.e., 1000/18 moles = 55.55 moles of water.
`THEREFORE "MOLE fraction of "CH_(3)OH`
`=(5.2)/(5.2+55.55)=0.086`


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