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A 5.25% solution of a substance is isotonic with a 1.5% solution of urea (molar mass = 60 g mol^(-1)) in the same solvent. If the densities of both solutions are assumed to be equal to 1.0 g cm^(-3), molar mass of the substance will be |
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Answer» `90.0 g mol^(-1)` Let the MOLAR MASS of the substances be M `pi = C_(1)RT=C_(2)RT=pi_(2)` So, `C_(1)=C_(2)` As DENSITY of the solutions are same So, `(5.25)/(M)=(15)/(60)RARR M =(5.25xx60)/(1.5)=210` |
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