1.

A 5.25% solution of a substance is isotonic with a 1.5% solution of urea (molar mass = 60g mol^(-1)) in the same solvent. If the densities of both the solutionsare assumed to be equal to 1.0 g cm^(-3), molar mass of the substance will be:

Answer»

210.0 G `mol^(-1)`
90.0g `mol^(-1)`
115.0 g `mol^(-1)`
105.0 g `mol^(-1)`

Solution :For the isotonic solutions
`pi_(1)=pi_(2)orC_(1)RT=C_(2)RT`
`W_(("urea"))/M_(("urea"))=W_("SUBSTANCE")/M_("substance")`
`((1.5g))/((60G mol^(-1)))=((5.25g))/M`
`M=((5.25 g)XX(60 g mol^(-1)))/((1.5g))`
`=210.0 g `mol^(-1)`


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