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A 5 cm cube of a substance has its upper surface displaced by 0.5 cm, by a tangential force of 0.25 N. What is the modulus of rigidity of the substance ? |
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Answer» Solution :`theta = x/L = 0.5 XX 10^(-2)// 5 xx 10^2 = 0.1` `eta = F//A tetha = 0.25/25 xx 10^(-4) xx 10^(-1) = 1000 N//m^2` |
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