A 5 kg stationary bomb is exploded in three parts having mass 1: 1: 3 respectively. Parts having same mass move in perpendicular direction with velocity 39 m/s, then the velocity of bigger part will be:

A 5 kg stationary bomb is exploded in three parts having mass 1: 1: 3

1.	A 5 kg stationary bomb is exploded in three parts having mass 1: 1: 3 respectively. Parts having same mass move in perpendicular direction with velocity 39 m/s, then the velocity of bigger part will be:
Answer» `13sqrt(2)` m/s `(10)/(SQRT(2))` m/s `15sqrt(2)` m/s `(15)/(sqrt(2))` m/s Solution :Here, mass of 3 PARTS wil be 1 kg , 1 kg and 3 kg. Applying conservation law of momentum `\|p^2\|=sqrt(p_1^2+p_2^2)` `(3xxV)^2=(1xx39)^2+(1xx39)^2` `V^2=1/9xx(39)^2(1+1)=((39)^2)/(9)xx2` `V=1/3xx39sqrt2=13sqrt2 MS^(-1)`

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A 5 kg stationary bomb is exploded in three parts having mass 1: 1: 3 respectively. Parts having same mass move in perpendicular direction with velocity 39 m/s, then the velocity of bigger part will be:

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