A 5 litre cylinder contained 10 moles of oxygen gas at `27^(@)C`. Due to sudden leakage through the hole, all the gas escaped into the atmosphere and the cylinder got empty. If the atmosphere pressure is 1.0 atm. Calculate the work done by the gas. Assuming gas to be ideal.

A 5 litre cylinder contained 10 moles of oxygen gas at `27^(@)C`. Due

1.	A 5 litre cylinder contained 10 moles of oxygen gas at `27^(@)C`. Due to sudden leakage through the hole, all the gas escaped into the atmosphere and the cylinder got empty. If the atmosphere pressure is 1.0 atm. Calculate the work done by the gas. Assuming gas to be ideal.
Answer» `V_("initial")=5` litre, `T=27^(@)C=27+273 = 300 K` `V_("final")=(nRT)/(P)=(10xx0.0821xx300)/(1)=246.3` litre `Delta V=V_("final")-V_("initial")=246.3-5=241.3` litre `W_("exp")=-P Delta V=-1xx241.3` litre `xx` atm. `=-24443.69J=24.4 kJ` i.e. work done by gas is 24.4 kJ

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A 5 litre cylinder contained 10 moles of oxygen gas at `27^(@)C`. Due to sudden leakage through the hole, all the gas escaped into the atmosphere and the cylinder got empty. If the atmosphere pressure is 1.0 atm. Calculate the work done by the gas. Assuming gas to be ideal.

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