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A 5 metre long wire is fixed to the ceiling. A weight of `10kg` is hung at the lower end and is `1metre` above the floor. The wire was elongated by `1mm`. The energy stored in the wire duw to streching isA. zeroB. `0.05joule`C. `100joule`D. `500joule` |
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Answer» Correct Answer - B `W=(1)/(2)xxFxxL=(1)/(2)mgl` `=(1)/(2)xx10xx10xx1xx10^-1=0.05J` |
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