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The work per unit volume to stretch the length by `1%` of a wire with cross sectional area of `1mm^2` will be. `[Y=9xx10^(11)(N)/(m^2)`]A. `9xx10^11J`B. `4.5xx10^7J`C. `9xx10^7J`D. `4.5xx10^11J` |
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Answer» Correct Answer - B `U=(1)/(2)xxYxx("strain")^2=(1)/(2)xx9xx10^11xx((1)/(100))^2` `=4.5xx10^7J` |
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