1.

A 5 muF capacitor is charged to a potential of 100 V and then disconnected from the power supply. Now it is connected in parallel to another capacitor of 20 muF. The common potential of the capacitors will be _____________ .

Answer»

SOLUTION :`20 V , V = (C_1 V_1)/(C_1 + C_2)= ((5muF) xx 100V)/((5 + 20 )muF) = 20V`


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