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A `50 Hz AC` source of `20 V` is connected across `R ` and `C` as shown in figureure. The voltage across `R` is `12 V`. The voltage across `C` isA. `8V`B. `16V`C. `10V`D. not possible to determine unless value of `R` and `C` are given |
Answer» Correct Answer - B `V_C=sqrt(V^2-V_R^2)=sqrt((20)^2-(12)^2)` `= 16V`. |
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