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A 50 muF capacitor is connected to an ac sourceV = 220 sin50t where V is in volt and t is in second. The rms current is

Answer»

0.55 A
`0.55/sqrt2A`
`sqrt2/0.55 A`
`sqrt2` A

Solution :On comparing V= 250 sin 50 t with
`V=V_0` sin `omegat` , we get
`V_0` =220 V and `omega=50 "RAD s"^(-1)`
`therefore` The capacitive REACTANCE is
`X_C=1/(omegaC)=1/((50 "rad s"^(-1))(50xx10^(-6) C))=10^4 /25 Omega`
`therefore` The rms CURRENT is `I_(rms)=V_(rms)/X_C=(V_0/sqrt2)/X_C(because V_(rms)=V_0/sqrt2)`
`= (220/sqrt2V)/(10^4/25 Omega)=(220xx25)/(10^4 XX sqrt2)A = 0.55/sqrt2`A


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