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A 500 g teapot and an insulated thermos are in a 20^(@)C room. The teapot is filled with 1000 g of the boiling water. 12 tea bags are then placed into the teapot. The brewed tea is allowed to cool to 80^(@)C, then 250 g of the tea is poured from the teapot into the thermos. The teapot is then kept on an insulated warmer that transfers 500 cal//min to the tea. Assume that the specific heat of brewed tea is the same as that of pure water, and that the tea bags have a very small mass compared to that of the water, and a negligible effect on the temperature. The specific heat of teapot is 0.17 J//gK and that of water is 4.18 J//gK. The entire procedure is done under atmospheric pressure. There are 4.18 J in one calorie. After the tea is added to the thermos, the temperature of the liquid quickly falls from 80^(@)C to 75^(@)C as it reaches thermal equilibrium with the thermos flask. What is the heat capacity of the thermos? |
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Answer» `9.5 J//K` `:.(ms)=95 J//k` (B)Granite (maximum SPECIFIC heat) (c) as Rate `=500cal//min.:.5min=2500`cal. `2500xx4.18=(750xx4.18+500xx0.17)Deltatheta` RIGHTARROW `Deltatheta=3.24` final temperature`=83.24^(@)`C |
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