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A 500 kg crave takes a turne of radius 50 m wiyh velocity of ` 54 km//h.The centripetal force isA. 1200 NB. 2250 VC. 750 ND. 250 N |
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Answer» Correct Answer - B `F=(mv^(2))/(r)=(500xx225)/(50)=2250 N` |
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