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A `500 Omega` resistor and a capacitor `C` are connected in series across `50 Hz AC` supply mains. The r.m.s potential difference recorded on voltmeter `V_(1)` and `V_(2)` are `V_(1)=120 V` and `V_(2)=160 V`. The power taken for the mains is: A. `480 W`B. `240 W`C. `28.8 W`D. `14.4 W` |
Answer» Correct Answer - C `V_(r.m.s)sqrt(V_(1)^(2)+V_(2)^(2))=sqrt(120^(2)+160^(2))` `I_(V)xx500=120, I_(V)=24A` `P_(av)=I_(V)^(2)R` |
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