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A 50MHz sky wave takes 4.04 ms to reach a receiver via retransmission from a satellite 600km above earht's surface. Assuming re-transmission time by satellite negligible, find the distance between source and reciever. |
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Answer» 606km Total time taken (t)`=("Total distance travelled"(2x))/("Speed of electromagnetic waves"(c))` ` therefore x=(CT)/(2)=((3xx10^(8))(4.04xx10^(-3))/(2)=6.06xx10^(5)m=606km` `therefore x=(ct)/(2)=((3xx10^(8))(4.04xx10^(-3)))/(2)=6.06xx10^(3)m=606km` Let T be the source of electromangetic waves (i.e. transmitter), R be receiver and S be sate as shown in FIGURE.  `d^(2)xxx^(2)-h^(2)=(606)^(2)-(600)^(2)` `therefore d= 85.06km` Distance between source and receiver `=2d=2xx85.06=170km ` |
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