1.

A 50muF capacitor is connected to a 100 V, 50 Hz ac supply. Determine the rms value of the current in the circuit.

Answer»

Solution :Here `C=50muF=50xx10^(-6)F=5xx10^(-5)F`
`E_("RMS")=100V, v=50Hz`.
Step 1. Capacitive REACTANCE,
`X_(C)=(1)/(Comega)=(1)/(Cxx2piv)=(1)/(5xx10^(-5)xx2xx3.14xx50)=63.69Omega`
Step 2. `I_("rms")=(E_("rms"))/(X_(C))=(100)/(63.69)=1.57A`


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