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A 60 muF capacitor is connected to a 110 V, 60 Hz a.c. supply. Determine the rms value of the current in the circuit. |
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Answer» Solution :Here, C = `60 muF = 60 xx 10^(-6) F, V_(rms) = 110V` and FREQUENCY v = 60 Hz `I_(rms) = V_(rms)/X_(C) = (V_(rms))/(1/C omega) = V_(rms).C.Omega.C.2piv` `=110 xx 60 xx 10^(-6) xx 2 xx 3.14 xx 60 = 2.49` A |
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