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A 60 muF capacitor is connected to a 110V, 60 Hz ac supply. Determine the rms value of the current in the circuit. |
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Answer» Solution :`X_(C) = ( 1)/( omega C )` ` = ( 1)/( 2PI f C )` ` = ( 1)/( 2 xx 3.14 xx 60 xx 60 xx 10^(-6))` `= 44.23 Omega` `I_(rms) = ( V_(rms))/( |Z|)` `= (V_(rms))/( X_(C))( :. `Here, `|Z| = X_(C )`) `= (110)/( 44.23)` `= 2.487 A` |
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