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A 60 V, 10 W lamp is to be run on 100 V, 60 Hz a.c. mains. Calculate the inductance of a chock required to be connected in series with it to work the bulb. |
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Answer» Solution :Resistacne of Lamp, `R = (V^(2))/(P) = ((60 xx 60))/(10) = 360 Omega` Current, `I_(rms) = (P)/(V) = (10)/(60) = (1)/(6)A` Impedance, `Z = (V_(rms))/(I_(rms)) = (100)/((1//6)) = 600 Omega` `Z = sqrt(R^(2) + XL^(2)) rArr L = (sqrt(Z^(2) - R^(2)))/(2pi f)` `L = (sqrt(600^(2) - 360^(2)))/(2(3.142)(60))` `= 1.273 H` |
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