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A 60 W load is connected to the secondary of a transformer whose primary draws line voltage. If a current of 0.54 A flows in the load, what is the current in the primary coil? Comment on the types of transformer being used. |
Answer» Correct Answer - A Given, `P_(s)=60 W, I_(s) = 0.54 A` Current in the primary `I_(p)=?` Taking line voltage as 220V. We can write Since, `P_(L) = 60 W, I_(L) = 0.54A` `rArr = V_(L)= 60/0.54=110V` Voltage in the secondary `(E_(s))` is less than voltage in the primary `(E_(p))`. Hence, the transfomer is step down transformer. Since, the transformation ratio `r=V_(s)/V_(p)= I_(p)/I_(s)` Substituting the values, `(110V)/(220V) = I_(p)/(0.54A)` On Solving `I_(p) =0.27A` |
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