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(a) 70 amu(c) 50 amuThe ragaseous mixturemolecules is(d) 021tio of masses of oxygen and nitrogen in a particular1:4. The ratio of number of their(a) 3:16(2014)lution ghtained by mixing 750 mL of(c) 7:32 |
Answer» let the mass of oxygen be x , and mass of nitrogen be 4x.. as given in question. now moles of oxygen be x/16 and , moles of nitrogen be 4x/14 so, ratio of their molecules is O/N = x/16/(4x/14) = 14/64 = 7/32.option C. this came in JEE MAIN 2014. I remember. |
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