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(a) A rod of length l is moved horizontal with a uniform velocity v in a direction perendicular to its length through a region in which a uniform magnetic field is acting vertically downward. Derive the expression for the emf induced across the end of the rod. (b) How does one understand this motional emf by invoking the Lorentz force acting on the free charge carriers of the conductor? Explain. |
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Answer» Solution :(a) Suppose a rod of LENGTH `I` moves with velocity V inward in the region having uniform magnetic FIELD B. Initial magnetic flux enclosed in the rectangular space is `s=|B|lx` As the rod moves with velocity `-V=(dx)/(dt)` Using Lenz's law `e=(dphi)/(dt)=-(d)/(dt)(BLX)=Bl((-dx)/(dt))`  (b) the magnetic force `vecq^v(xx)vecB` component of the Lorentz force is responsible for MOTIONAL electromotive force. When a conductor is moved through a magneticfield, the magnetic force tries to push the free electrons through the wire, and this CREATES the motional EMF. |
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