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(a) An iron ring of relative permeability mu_(r)has windings of insulated copper wire of n turns per metre. When the current in the windings is I, find the expression for the magnetic field in the ring. (b) The susceptibility of a magnetic material is 0.9853. Identify the type of magnetic material. Draw the modification of the field pattern on keeping a piece of this material in a uniform magnetic field. |
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Answer» Solution :From Ampere.s circuital ,we have ` oint oversetto B d oversetto I =MU _ 0 mu , I_("enclosed")` For the field inside the ring , we can write `oint oversetto B d oversetto I =oint Bdl =B = 2pi r` ( r= radius of the ring )USING equation (i) ` therefore B = 2pi , = mu _0 mu_r .(2pin)l` ` therefore B= mu _ 0 mu_tnl ` [Award those `((1)/(2) + ( 1) /(2)) `makeeven file the RESULT is written without giving the derivation] 
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