A and B are two events such that P(A) = 0.25 and P(B) = 0.50. The prob

1.	A and B are two events such that P(A) = 0.25 and P(B) = 0.50. The probability of both happening together is 0.14. The probability of both A and B not happening is A. 0.39B. 0.25C. 0.11D. none of these
Answer» Correct option is A. 0.39 Given P(A∪B) = 0.14,P(A) = 0.25,P(B) = 0.50 By addition theorem, P(A∪B) = P(A) + P(B) - P(A∩B) P(A∩B) = 0.75 - 0.14 = 0.61 ∴P(both A and B not happening) = 1 - P(A∩B) = 1 - 0.61 = 0.39

A and B are two events such that P(A) = 0.25 and P(B) = 0.50. The probability of both happening together is 0.14. The probability of both A and B not happening is A. 0.39B. 0.25C. 0.11D. none of these

Answer»

Correct option is A. 0.39

Given P(A∪B) = 0.14,P(A) = 0.25,P(B) = 0.50

By addition theorem,

P(A∪B) = P(A) + P(B) - P(A∩B) P(A∩B)

= 0.75 - 0.14 = 0.61

∴P(both A and B not happening) = 1 - P(A∩B) = 1 - 0.61 = 0.39

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A and B are two events such that P(A) = 0.25 and P(B) = 0.50. The probability of both happening together is 0.14. The probability of both A and B not happening is A. 0.39B. 0.25C. 0.11D. none of these

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