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A and B are two events such that P(A) = 0.8,P(B) = 0.5 and P(B/A) = 0.4, then Find P(A/B) |
Answer» Given: P(A/B) = 0.4 \(\frac{P(A∩ B)}{P(A)} = 0.4\\=\frac{P(A∩ B)}{0.8}=0.4\\=P(A∩ B)=0.32\\=\\P(\frac{A}{B}) = \frac{P(A∩ B)}{P(B)}\\=\frac{0.32}{0.5}\\=0.64\) |
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