1.

A and b can do a piece of work in 12 days b and c in 15 days c and a in 20 days in how many days build a complete it together and separately tell tell bi explanation​

Answer»

Hope it helps you...Step-by-step explanation:Let A, B & C do the work SEPARATELY in a, b & c days separately. Given, A and B can do a PIECE of work in 12 days . => 1/a + 1/b = 1/12—————(1) Given, B and C can do a piece of work in 15 days => 1/b + 1/c = 1/15—————(2) Given, C and A can do a piece of work in 20 days => 1/c + 1/a = 1/20—————(3) Adding all the three EQUATIONS, 2(1/a + 1/b + 1/c) = 1/12 + 1/15 + 1/20 2(1/a + 1/b + 1/c) = (5+4+3)/60 = 12/60 = 1/5 => 1/a + 1/b + 1/c = 1/10———(4) (4) - (1) => (1/a + 1/b + 1/c) - (1/a + 1/b) = 1/10 - 1/12 = (6–5)/60 = 1/60 => 1/c = 1/60 => c = 60 => C takes 60 days to do the work separately. (4) - (2) =>(1/a + 1/b + 1/c) - (1/b + 1/c) = 1/10 - 1/15 = (3–2)/30 = 1/30 => 1/a = 1/30 => a = 30 => A takes 30 days to do the work separately. (4) - (3) =>(1/a + 1/b + 1/c) - (1/c + 1/a) = 1/10 - 1/20 = (2–1)/20 = 1/20 => 1/b = 1/20 => b = 20 => B takes 20 days to do the work separately.Please mark as brainliest if it really helps you...❤❤❤



Discussion

No Comment Found