A And B Completed A Work Together In 5 Days. Had A Worked At Twice Th

1.	A And B Completed A Work Together In 5 Days. Had A Worked At Twice The Speed And B At Half The Speed, It Would Have Taken Them Four Days To Complete The Job. How Much Time Would It Take For A Alone To Do The Work?
Answer» As A and B completed a work together in 5 days Work done by them in a day (A + B), 1/5 with TWICE the speed of A and half the speed of B , they COMPLETES the work in 4 days, so, their work per day (2A + B/2) = 1/4 by solving both the eqns: 2(2A+B/2) – (A+B) = 3A = 21/4 – 1/5 = 3/10 or 1-day work of A = 1/10 so A ALONE can complete the work in 10 days. As A and B completed a work together in 5 days Work done by them in a day (A + B), 1/5 with twice the speed of A and half the speed of B , they completes the work in 4 days, so, their work per day (2A + B/2) = 1/4 by solving both the eqns: 2(2A+B/2) – (A+B) = 3A = 21/4 – 1/5 = 3/10 or 1-day work of A = 1/10 so A alone can complete the work in 10 days.

A And B Completed A Work Together In 5 Days. Had A Worked At Twice The Speed And B At Half The Speed, It Would Have Taken Them Four Days To Complete The Job. How Much Time Would It Take For A Alone To Do The Work?

Answer»

As A and B completed a work together in 5 days

Work done by them in a day (A + B), 1/5

with TWICE the speed of A and half the speed of B , they COMPLETES the work in 4 days,

so, their work per day (2A + B/2) = 1/4

by solving both the eqns: 2(2A+B/2) – (A+B) = 3A = 2*1/4 – 1/5 = 3/10

or 1-day work of A = 1/10

so A ALONE can complete the work in 10 days.

As A and B completed a work together in 5 days

Work done by them in a day (A + B), 1/5

with twice the speed of A and half the speed of B , they completes the work in 4 days,

so, their work per day (2A + B/2) = 1/4

by solving both the eqns: 2(2A+B/2) – (A+B) = 3A = 2*1/4 – 1/5 = 3/10

or 1-day work of A = 1/10

so A alone can complete the work in 10 days.

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