1.

Car A Leaves City C At 5 Pm And Drives At A Speed Of 40 Kmph. 2 Hours Later Another Car B Leaves City C And Drives In The Same Direction As Car A. In How Much Time Will Car B Be 9 Km Ahead Of Car A. Speed Of Car B Is 60 Kmph.

Answer»

Let after t time two cars will met.

So A will TRAVEL distance of 40t with 40kmph

B will travel the distance of 60t with 60kmph

And ALSO A is ahead 80 km (40*2=80) from B

=> 60t - 40t = 80 => t = 4hrs

Also time taken by B to COVER 9kms more is 9/60 = 9mins

Additional distance is 9 min

For additional time= (9/20) *60=27 min

So correct answer = 4hrs 27 min

= 4 (27/60) hrs = 4.45 hrs

Let after t time two cars will met.

So A will travel distance of 40t with 40kmph

B will travel the distance of 60t with 60kmph

And also A is ahead 80 km (40*2=80) from B

=> 60t - 40t = 80 => t = 4hrs

Also time taken by B to cover 9kms more is 9/60 = 9mins

Additional distance is 9 min

For additional time= (9/20) *60=27 min

So correct answer = 4hrs 27 min

= 4 (27/60) hrs = 4.45 hrs



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