InterviewSolution
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Car A Leaves City C At 5 Pm And Drives At A Speed Of 40 Kmph. 2 Hours Later Another Car B Leaves City C And Drives In The Same Direction As Car A. In How Much Time Will Car B Be 9 Km Ahead Of Car A. Speed Of Car B Is 60 Kmph. |
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Answer» Let after t time two cars will met. So A will TRAVEL distance of 40t with 40kmph B will travel the distance of 60t with 60kmph And ALSO A is ahead 80 km (40*2=80) from B => 60t - 40t = 80 => t = 4hrs Also time taken by B to COVER 9kms more is 9/60 = 9mins Additional distance is 9 min For additional time= (9/20) *60=27 min So correct answer = 4hrs 27 min = 4 (27/60) hrs = 4.45 hrs Let after t time two cars will met. So A will travel distance of 40t with 40kmph B will travel the distance of 60t with 60kmph And also A is ahead 80 km (40*2=80) from B => 60t - 40t = 80 => t = 4hrs Also time taken by B to cover 9kms more is 9/60 = 9mins Additional distance is 9 min For additional time= (9/20) *60=27 min So correct answer = 4hrs 27 min = 4 (27/60) hrs = 4.45 hrs |
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